# `del` statement

## Basic

```py
a = 1
del a
# error: [unresolved-reference]
reveal_type(a)  # revealed: Unknown

# error: [invalid-syntax] "Invalid delete target"
del 1

# error: [unresolved-reference]
del a

x, y = 1, 2
del x, y
# error: [unresolved-reference]
reveal_type(x)  # revealed: Unknown
# error: [unresolved-reference]
reveal_type(y)  # revealed: Unknown

def cond() -> bool:
    return True

b = 1
if cond():
    del b

# error: [possibly-unresolved-reference]
reveal_type(b)  # revealed: Literal[1]

c = 1
if cond():
    c = 2
else:
    del c

# error: [possibly-unresolved-reference]
reveal_type(c)  # revealed: Literal[2]

d = [1, 2, 3]

def delete():
    del d  # error: [unresolved-reference] "Name `d` used when not defined"

delete()
reveal_type(d)  # revealed: list[int]

def delete_element():
    # When the `del` target isn't a name, it doesn't force local resolution.
    del d[0]
    print(d)

def delete_global():
    global d
    del d
    # We could lint that `d` is unbound in this trivial case, but because it's global we'd need to
    # be careful about false positives if `d` got reinitialized somehow in between the two `del`s.
    del d

delete_global()
# Again, the variable should have been removed, but we don't check it.
reveal_type(d)  # revealed: list[int]

def delete_nonlocal():
    e = 2

    def delete_nonlocal_bad():
        del e  # error: [unresolved-reference] "Name `e` used when not defined"

    def delete_nonlocal_ok():
        nonlocal e
        del e
        # As with `global` above, we don't track that the nonlocal `e` is unbound.
        del e
```

## `del` forces local resolution even if it's unreachable

Without a `global x` or `nonlocal x` declaration in `foo`, `del x` in `foo` causes `print(x)` in an
inner function `bar` to resolve to `foo`'s binding, in this case an unresolved reference / unbound
local error:

```py
x = 1

def foo():
    print(x)  # error: [unresolved-reference] "Name `x` used when not defined"
    if False:
        # Assigning to `x` would have the same effect here.
        del x

    def bar():
        print(x)  # error: [unresolved-reference] "Name `x` used when not defined"
```

## But `del` doesn't force local resolution of `global` or `nonlocal` variables

However, with `global x` in `foo`, `print(x)` in `bar` resolves in the global scope, despite the
`del` in `foo`:

```py
x = 1

def foo():
    global x
    def bar():
        # allowed, refers to `x` in the global scope
        reveal_type(x)  # revealed: Literal[1]
    bar()
    del x  # allowed, deletes `x` in the global scope (though we don't track that)
```

`nonlocal x` has a similar effect, if we add an extra `enclosing` scope to give it something to
refer to:

```py
def enclosing():
    x = 2
    def foo():
        nonlocal x
        def bar():
            # allowed, refers to `x` in `enclosing`
            reveal_type(x)  # revealed: Literal[2]
        bar()
        del x  # allowed, deletes `x` in `enclosing` (though we don't track that)
```

## Delete attributes

If an attribute is referenced after being deleted, it will be an error at runtime. But we don't
treat this as an error (because there may have been a redefinition by a method between the `del`
statement and the reference). However, deleting an attribute invalidates type narrowing by
assignment, and the attribute type will be the originally declared type.

### Invalidate narrowing

```py
class C:
    x: int = 1

c = C()
del c.x
reveal_type(c.x)  # revealed: int

# error: [unresolved-attribute]
del c.non_existent

c.x = 1
reveal_type(c.x)  # revealed: Literal[1]
del c.x
reveal_type(c.x)  # revealed: int
```

### Delete an instance attribute definition

```py
class C:
    x: int = 1

c = C()
reveal_type(c.x)  # revealed: int

del C.x
c = C()
# This attribute is unresolved, but we won't check it for now.
reveal_type(c.x)  # revealed: int
```

## Delete items

### Basic item deletion

Deleting an item also invalidates the narrowing by the assignment, but accessing the item itself is
still valid.

```py
def f(l: list[int]):
    del l[0]
    # If the length of `l` was 1, this will be a runtime error,
    # but if it was greater than that, it will not be an error.
    reveal_type(l[0])  # revealed: int

    # error: [invalid-argument-type]
    del l["string"]

    l[0] = 1
    reveal_type(l[0])  # revealed: Literal[1]
    del l[0]
    reveal_type(l[0])  # revealed: int
```

### `__delitem__` without `__getitem__`

A class or protocol that only defines `__delitem__` (without `__getitem__`) should still support
item deletion. The `__delitem__` method is independent of `__getitem__`.

```py
from typing import Protocol, TypeVar

KT = TypeVar("KT")

class CanDelItem(Protocol[KT]):
    def __delitem__(self, k: KT, /) -> None: ...

def f(x: CanDelItem[int], k: int):
    # This should be valid - the object has __delitem__
    del x[k]

class OnlyDelItem:
    def __delitem__(self, key: int) -> None:
        pass

d = OnlyDelItem()
del d[0]  # OK

# error: [not-subscriptable] "Cannot subscript object of type `OnlyDelItem` with no `__getitem__` method"
d[0]
```

### `__getitem__` without `__delitem__`

A class that only defines `__getitem__` (without `__delitem__`) should not support item deletion.

```py
class OnlyGetItem:
    def __getitem__(self, key: int) -> str:
        return "value"

g = OnlyGetItem()
reveal_type(g[0])  # revealed: str

# error: [not-subscriptable] "Cannot delete subscript on object of type `OnlyGetItem` with no `__delitem__` method"
del g[0]
```

### TypedDict deletion

Deleting a required key from a TypedDict is a type error because it would make the object no longer
a valid instance of that TypedDict type. However, deleting `NotRequired` keys (or keys in
`total=False` TypedDicts) is allowed.

<!-- snapshot-diagnostics -->

```py
from typing_extensions import TypedDict, NotRequired

class Movie(TypedDict):
    name: str
    year: int

class PartialMovie(TypedDict, total=False):
    name: str
    year: int

class MixedMovie(TypedDict):
    name: str
    year: NotRequired[int]

m: Movie = {"name": "Blade Runner", "year": 1982}
p: PartialMovie = {"name": "Test"}
mixed: MixedMovie = {"name": "Test"}

# Required keys cannot be deleted.
# error: [invalid-argument-type]
del m["name"]

# In a partial TypedDict (`total=False`), all keys can be deleted.
del p["name"]

# `NotRequired` keys can always be deleted.
del mixed["year"]

# But required keys in mixed `TypedDict` still cannot be deleted.
# error: [invalid-argument-type]
del mixed["name"]

# And keys that don't exist cannot be deleted.
# error: [invalid-argument-type]
del mixed["non_existent"]
```
